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authorepoch <epoch@hacking.allowed.org>2019-02-05 21:48:29 -0600
committerepoch <epoch@hacking.allowed.org>2019-02-05 21:48:29 -0600
commit420eeee620a287ac5bf133f8a17329a7182d5bbf (patch)
tree407cd59748e0e5ef4f88b15305dd303aa64cf8da /bin/embolden
parent848a823b1287d8804e8d6170c3ca30ccf7689784 (diff)
downloadhackvr-420eeee620a287ac5bf133f8a17329a7182d5bbf.tar.gz
hackvr-420eeee620a287ac5bf133f8a17329a7182d5bbf.zip
forgot to add bin dir that contains a LOT of the handy stuff
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+/*
+
+so, we have a line.
+
+from 0,0 to 10,0
+
+and we want it to transform into a rectangle at about...
+
+-1,-1 1,-1 1,11 -1,11
+
+I guess we're taking each point and pushing it away from itself.
+
+so 0,0... we can make into a square. we need to push in a direction based on the direction of the other half of the line
+
+so a=points_to_angle(p1,p2)
+
+which is 90deg in this case from 0,0 to 10,0
+and we need to push 0,0 in two directions to create two new points
+at angles...
+90+135 and 90+135+90
+
+a+135 and a+135+90
+
+now to pick an emboldeness amount. sqrt(2) will get us to the original points I guessed at earlier.
+
+#define embolden(p1,p2,angle,dist)
+
+if(s.len == 2) {
+ a1=points_to_angle(p1,p2);
+ a2=points_to_angle(p2,p1);
+ d=1;//how far to embolden
+ //a2 = (a1 + 180) % 360
+ s[0]=c3_add(s.p[0],(c3_t){sin(a2+45)*d,cos(a2+45)*d,0})
+ s[1]=c3_add(s.p[0],(c3_t){sin(a2-45)*d,cos(a2-45)*d,0})
+ s[2]=c3_add(s.p[1],(c3_t){sin(a1+45)*d,cos(a1+45)*d,0})
+ s[3]=c3_add(s.p[1],(c3_t){sin(a1-45)*d,cos(a1-45)*d,0})
+}
+
+//this can be a script. it'll turn lines into rectangles.
+//could be done with awk probably.
+//base it on offsetshape?
+//maybe just do it in python.